A soap film of thickness 0.3 μ m appears dark when seen by the refracted light of wavelength 580 nm. What is the index of refraction of the soap solution, if it is known to be between 1.3 and 1.5?
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(1.45 )
Sol. The path difference is 2 μ t.
Now for destructive interface it can be
2 μ t = 
or 
or 
and so on .........
μ = 
, 
, 
.....
= 
, 
................
= 0.4833 , 3 × 0.4833..............
so only μ = 3 × 0.4833 = 1.45 is the answer, {1.3 < μ < 1.5}
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